Skip to main content

Ada and Dishes Codechef November long challenge problem solution

 Ada and Dishes Codechef November long challenge problem solution -


Problem Statement-

Chef Ada is preparing N dishes (numbered 1 through N). For each valid i, it takes Ci minutes to prepare the i-th dish. The dishes can be prepared in any order.

Ada has a kitchen with two identical burners. For each valid i, to prepare the i-th dish, she puts it on one of the burners and after Ci minutes, removes it from this burner; the dish may not be removed from the burner before those Ci minutes pass, because otherwise it cools down and gets spoiled. Any two dishes may be prepared simultaneously, however, no two dishes may be on the same burner at the same time. Ada may remove a dish from a burner and put another dish on the same burner at the same time.

What is the minimum time needed to prepare all dishes, i.e. reach the state where all dishes are prepared?

Input

  • The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.
  • The first line of each test case contains a single integer N.
  • The second line contains N space-separated integers C1,C2,,CN.

Output

For each test case, print a single line containing one integer ― the minimum number of minutes needed to prepare all dishes.

Constraints

  • 1T1,000
  • 1N4
  • 1Ci5 for each valid i

Subtasks

Subtask #1 (1 points): C1=C2==CN

Subtask #2 (99 points): original constraints

Example Input

3
3
2 2 2
3
1 2 3
4
2 3 4 5

Example Output

4
3
7

Explanation

Example case 1: Place the first two dishes on the burners, wait for two minutes, remove both dishes and prepare the last one on one burner.

Example case 2: Place the first and third dish on the burners. When the first dish is prepared, remove it and put the second dish on the same burner.

Example case 3: Place the third and fourth dish on the burners. When the third dish is prepared, remove it and put the second dish on the same burner. Similarly, replace the fourth dish (when it is prepared) by the first dish on the other burner.

Ada and Dishes Codechef November long challenge problem solution


Solution-

This is very simple problem.
First of  all sort array and 
Start iterating from array form right two left and make two burners and start assigning value to each burner.
if(burnur1<burnur2){
               burnur1+=v[i];
            if(max<burnur1)
            max=burnur1;
           }
           else{
               burnur2+=v[i];
                if(max<burnur2)
            max=burnur2;
           }
At last print value of max.
Follow code below.


Must Join Telegram channel for Editorial -

December Long Challege Solution -

link- https://www.technicalkeeda.in/2020/11/codechef-december-long-challenge-editorial.html






Comments

Popular posts from this blog

Vaccine Distribution Codechef December Long challenge solution 2020

 Vaccine Distribution  Codechef December Long challenge solution 2020- This Problem vaccine distribution is taken from December long challenge 2020. lets read problem statement. Problem statement- Finally, a COVID vaccine is out on the market and the Chefland government has asked you to form a plan to distribute it to the public as soon as possible. There are a total of  N N  people with ages  a 1 , a 2 , … , a N a 1 , a 2 , … , a N . There is only one hospital where vaccination is done and it is only possible to vaccinate up to  D D  people per day. Anyone whose age is  ≥ 80 ≥ 80  or  ≤ 9 ≤ 9  is considered to be  at risk . On each day, you may not vaccinate both a person who is at risk and a person who is not at risk. Find the smallest number of days needed to vaccinate everyone. Input The first line of the input contains a single integer  T T  denoting the number of test cases. The description of  T T  test cases follows. The first line of each test case contains two space-separ

Codechef February long challenge solution 2021

   Codechef February  long challenge solution 2021- Hey guys Welcome Again, A small update CodeChef February  long challenge solution 2021 starting from 1st week of beb  2021 . Codechef long challenge is one of the popular contests of CodeChef you should participate in codechef Feb  long challenge.This is first contest of codechef in 2021 so good luck. And wish you happy new year. Contest link- https://www.codechef.com/FEB21/?itm_medium=navmenu&itm_campaign=FEB21 I will post the solution after Contest.Stay tuned. About CodeChef  February  long challenge solution 2021: CodeChef Long Challenge is a 10-day monthly coding contest where you can show off your computer programming skills. The significance being - it gives you enough time to think about a problem, try different ways of attacking the problem, read the concepts etc. If you’re usually slow at solving problems and have ample time at hand, this is ideal for you. We also put in a lot of efforts in getting quality problems, w

Merge Two sorted array Without Extra Space

Problem statement-  Given two sorted arrays arr1[] and arr2[] of sizes N and M in non-decreasing order. Merge them in sorted order without using any extra space. Modify arr1 so that it contains the first N elements and modify arr2 so that it contains the last M elements.    Example 1: Input:  N = 4, arr1[] = [1 3 5 7]  M = 5, arr2[] = [0 2 6 8 9] Output:  arr1[] = [0 1 2 3] arr2[] = [5 6 7 8 9] Explanation: After merging the two  non-decreasing arrays, we get,  0 1 2 3 5 6 7 8 9.   Example 2: Input:  N = 2, arr1[] = [10, 12]  M = 3, arr2[] = [5 18 20] Output:  arr1[] = [5 10] arr2[] = [12 18 20] Explanation: After merging two sorted arrays  we get 5 10 12 18 20. Your Task: You don't need to read input or print anything. You only need to complete the function merge() that takes arr1, arr2, N and M as input parameters and modifies them in-place so that they look like the sorted merged array when concatenated. Expected Time Complexity:  O((n+m) log(n+m)) Expected Auxilliary Space: O(1