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Chef and IPC Certificates codechef November cook off challenge solution

 Chef and IPC Certificates  codechef November cook off challenge solution-

Problem statement-

There were N students (numbered 1 through N) participating in the Indian Programming Camp (IPC) and they watched a total of K lectures (numbered 1 through K). For each student i and each lecture j, the i-th student watched the j-th lecture for Ti,j minutes.

Additionally, for each student i, we know that this student asked the question, "What is the criteria for getting a certificate?" Qi times.

The criteria for getting a certificate is that a student must have watched at least M minutes of lectures in total and they must have asked the question no more than 10 times.

Find out how many participants are eligible for a certificate.

Input

  • The first line of the input contains three space-separated integers NM and K.
  • N lines follow. For each valid i, the i-th of these lines contains K+1 space-separated integers Ti,1,Ti,2,,Ti,K,Qi.

Output

Print a single line containing one integer — the number of participants eligible for a certificate.

Constraints

  • 1N,K1,000
  • 1M106
  • 1Qi106 for each valid i
  • 1Ti,j1,000 for each valid i and j

Example Input

4 8 4
1 2 1 2 5
3 5 1 3 4
1 2 4 5 11
1 1 1 3 12

Example Output

1

Explanation

  • Participant 1 watched 1+2+1+2=6 minutes of lectures and asked the question 5 times. Since 6<M, this participant does not receive a certificate.
  • Participant 2 watched 3+5+1+3=12 minutes of lectures and asked the question 4 times. Since 12M and 410, this participant receives a certificate.
  • Participant 3 watched 1+2+4+5=12 minutes of lectures and asked the question 11 times. Since 12M but 11>10, this participant does not receive a certificate.
  • Participant 4 watched 1+1+1+3=6 minutes of lectures and asked the question 12 times. Since 6<M and 12>10, this participant does not receive a certificate.

Only participant 2 receives a certificate.

link -https://www.codechef.com/COOK124B/problems/IPCCERT

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Solution -

this problem can be solved by using brute force approach .

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