## Vaccine Distribution  Codechef December Long challenge solution 2020-

This Problem vaccine distribution is taken from December long challenge 2020. lets read problem statement.

### Problem statement-

Finally, a COVID vaccine is out on the market and the Chefland government has asked you to form a plan to distribute it to the public as soon as possible. There are a total of $N$ people with ages ${a}_{1},{a}_{2},\dots ,{a}_{N}$.

There is only one hospital where vaccination is done and it is only possible to vaccinate up to $D$ people per day. Anyone whose age is $\ge 80$ or $\le 9$ is considered to be at risk. On each day, you may not vaccinate both a person who is at risk and a person who is not at risk. Find the smallest number of days needed to vaccinate everyone.

### Input

• The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.
• The first line of each test case contains two space-separated integers $N$ and $D$.
• The second line contains $N$ space-separated integers ${a}_{1},{a}_{2},\dots ,{a}_{N}$.

### Output

For each test case, print a single line containing one integer ― the smallest required number of days.

### Constraints

• $1\le T\le 10$
• $1\le N\le {10}^{4}$
• $1\le D\le {10}^{5}$
• $1\le {a}_{i}\le 100$ for each valid $i$

Subtask #1 (100 points): original constraints

### Example Input

2
10 1
10 20 30 40 50 60 90 80 100 1
5 2
9 80 27 72 79


### Example Output

10
3


### Explanation

Example case 1: We do not need to worry about how the people are grouped, since only one person can be vaccinated in a single day. We require as many days as there are people.

Example case 2: There are two people at risk and three people who are not at risk. One optimal strategy is to vaccinate the two people at risk on day $1$ and the remaining three on the next $2$ days. #### Solution-

Hint- This Problem can be solved using the brute force approach. make count of risky and non riskey person .

The problem can be solved by using simple if else statement follow my code i don't think there is a need for explanation.
For reference my code is mention below.
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