Codechef November long challenge solution | November long challenge solution

Codechef November long challenge solution-

Hey guys Welcome Again, A small update codechef November long challenge starting from 6th November 2020 to 16 th November 2020.Codechef long challenge is one of the popular contest of codechef you should participate in codechef November long challenge.

Contest link-https://www.codechef.com/NOV20/?itm_campaign=NOV20

Codechef November long challenge solution | November long challenge solution

I will post solution after 16 November.Stay tuned.

About CodeChef November Long Challenge:

CodeChef Long Challenge is a 10-day monthly coding contest where you can show off your computer programming skills. The significance being - it gives you enough time to think about a problem, try different ways of attacking the problem, read the concepts etc. If you’re usually slow at solving problems and have ample time at hand, this is ideal for you. We also put in a lot of efforts in getting quality problems, which would, in turn, foster your learning while solving them.

1st problem - ADA and Dishes

2nd problem- Restore sequence solution

3rd problem -Iron magnet and wall

4th problem- Magical candy solution

Past contest Editorial- CodeChef Long challenge editorial | codechef long challenge solutions

CodeChef October Lunchtime Problem Solution | codechef Lunctime Problem solution

Join Telegram channel for code - https://t.me/competitiveProgrammingDiscussion

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Apple Division CSES Problem Set Solution | CSES Problem Set Solution Apple division with code

Apple Division CSES Problem Set Solution | CSES Problem Set Solution Apple division with code - Apple Division CSES Problem Solution Easy Explanation. Apple division is problem is taken form cses introductory problem set.Let's Read Problem statement first. Problem Statement- Time limit: 1.00 s Memory limit: 512 MB There are n n apples with known weights. Your task is to divide the apples into two groups so that the difference between the weights of the groups is minimal. Input The first input line has an integer n n : the number of apples. The next line has n n integers p 1 , p 2 , … , p n p 1 , p 2 , … , p n : the weight of each apple. Output Print one integer: the minimum difference between the weights of the groups. Constraints 1 ≤ n ≤ 20 1 ≤ n ≤ 20 1 ≤ p i ≤ 10 9 1 ≤ p i ≤ 10 9 Example Input: 5 3 2 7 4 1 Output: 1 Explanation: Group 1 has weights 2, 3 and 4 (total weight 9), and group 2 has weights 1 and 7 (total weight 8). Join Telegram channel for code discussi

Movie Festival CSES problem set solution

Movie Festival CSES problem set solution - Problem statement- Time limit: 1.00 s Memory limit: 512 MB In a movie festival n n movies will be shown. You know the starting and ending time of each movie. What is the maximum number of movies you can watch entirely? Input The first input line has an integer n n : the number of movies. After this, there are n n lines that describe the movies. Each line has two integers a a and b b : the starting and ending times of a movie. Output Print one integer: the maximum number of movies. Constraints 1 ≤ n ≤ 2 ⋅ 10 5 1 ≤ n ≤ 2 ⋅ 10 5 1 ≤ a < b ≤ 10 9 1 ≤ a < b ≤ 10 9 Example Input: 3 3 5 4 9 5 8 Output: 2 Solution - Step -1 take input in a vector as a pair first element is ending time ans second element is starting time Step -2 sort the vector in increasing order because we will watch that movie which is ending first. Step -3 iterate over vector and calculate ans . follow code below-

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